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c=1
f(-3/2)=0⇔a*(-3/2)+b=0⇔b=3/2)*a
-8=(-1/2)a+b]/(-1/2+1)
-8=2[a]
a=-4
b=-6
y=(-4x-6)/(x+1)
c)
0 rozw. dla m∈(-∞,0)
1 dla m=0
2 dla m∈(0,∞)-{3}