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zd7
I=20
II= 14
III Pb=2πrh r=10 h=14 π=3
Pb=2*3*10*14= 840 cm²
IV Pc=Pb+Pp Pp=πr²=3*10²=300
Pc=840+300=1140 cm²
V=πr²h
V=3*10²*14=4200 cm³
zd8
r=5
h=10√2
obl tworzaca L, powstaje tr. prostokatny
5²+(10√2)²=L²
L²=25+200=225
L=√225=15 tworzaca
V=1/3πr²h
V=1/3 *3*5² *10√2=250√2
zd9
I α=90 β=45
II mamy trojkąt równoramienny(bo katy po 45 st) i prostokątny
wiec r=h
r²+r²=L²
2r²=(8√2)²
2r²=64*2
r²=64
r=8
III h=r=8
IV V=1/3πr²h
V=1/3*3*8²*8=512 cm³