PROSZĘ O POMOC I WYTŁUMACZENIE
DAM NAJ ZA POPRAWNE WYLICZENIA.
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ola737626
October 2020 | 0 Replies
BŁAGAM POMÓŻCIE PLIIIISSSSSSSS ❤️❤️❤️ DAJE ❤️ I NAJ!!!!!! BĘDĘ WDZIĘCZNA PLISSSSSSSSS...W tabeli (w załączniku) podano wyniki zakończonego sezonu szkolnej ligi piłkarskiej każda z drużyn rozegrała 10 meczów. Za wygrany mecz otrzymywała 3 punkty za remis 1 punkt a za porażkę 0 punktówWykonaj polecenie i napisz działanie Niebiescy w 10 meczach zdobyli 26 punktów. Ile razy odnieśli zwycięstwo A ile razy zremisowali
a)![8^{\frac{1}{3}}=\sqrt[3]{8}=\sqrt[3]{2*2*2}=2](https://tex.z-dn.net/?f=8%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B8%7D%3D%5Csqrt%5B3%5D%7B2%2A2%2A2%7D%3D2 "8^{\frac{1}{3}}=\sqrt[3]{8}=\sqrt[3]{2*2*2}=2")
b)![16^{\frac{3}{2}}=\sqrt[2]{16^3}=4^3=64](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%3D%5Csqrt%5B2%5D%7B16%5E3%7D%3D4%5E3%3D64 "16^{\frac{3}{2}}=\sqrt[2]{16^3}=4^3=64")
c)![16^{\frac{1}{4}}=\sqrt[4]{16}=\sqrt[4]{2*2*2*2}=2](https://tex.z-dn.net/?f=16%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B16%7D%3D%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%3D2 "16^{\frac{1}{4}}=\sqrt[4]{16}=\sqrt[4]{2*2*2*2}=2")
ć)![25^{ \frac{3}{2}}=\sqrt[2]{25^3}=5^3=125](https://tex.z-dn.net/?f=25%5E%7B+%5Cfrac%7B3%7D%7B2%7D%7D%3D%5Csqrt%5B2%5D%7B25%5E3%7D%3D5%5E3%3D125 "25^{ \frac{3}{2}}=\sqrt[2]{25^3}=5^3=125")
d)![2^{\frac{1}{4}}*8^{\frac{1}{4}}=\sqrt[4]{2}*\sqrt[4]{8}=\sqrt[4]{2*8}=\sqrt[4]{2*2*2*2}=2](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%2A8%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B2%7D%2A%5Csqrt%5B4%5D%7B8%7D%3D%5Csqrt%5B4%5D%7B2%2A8%7D%3D%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%3D2 "2^{\frac{1}{4}}*8^{\frac{1}{4}}=\sqrt[4]{2}*\sqrt[4]{8}=\sqrt[4]{2*8}=\sqrt[4]{2*2*2*2}=2")
e)![7^{\frac{2}{5}}*7^{\frac{3}{5}}=\sqrt[5]{7^2}*\sqrt[5]{7^3}=\sqrt[5]{7^5}=7](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B2%7D%7B5%7D%7D%2A7%5E%7B%5Cfrac%7B3%7D%7B5%7D%7D%3D%5Csqrt%5B5%5D%7B7%5E2%7D%2A%5Csqrt%5B5%5D%7B7%5E3%7D%3D%5Csqrt%5B5%5D%7B7%5E5%7D%3D7 "7^{\frac{2}{5}}*7^{\frac{3}{5}}=\sqrt[5]{7^2}*\sqrt[5]{7^3}=\sqrt[5]{7^5}=7")
ę)![2^{\frac{1}{3}}*4^{\frac{1}{3}}=\sqrt[3]{2}*\sqrt[3]{4}=\sqrt[3]{2*2^2}=\sqrt[3]{2^3}=2](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%2A4%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B2%7D%2A%5Csqrt%5B3%5D%7B4%7D%3D%5Csqrt%5B3%5D%7B2%2A2%5E2%7D%3D%5Csqrt%5B3%5D%7B2%5E3%7D%3D2 "2^{\frac{1}{3}}*4^{\frac{1}{3}}=\sqrt[3]{2}*\sqrt[3]{4}=\sqrt[3]{2*2^2}=\sqrt[3]{2^3}=2")
f)![4^{\frac{1}{6}}*4^{\frac{5}{6}}=\sqrt[6]{4}*\sqrt[6]{4^5}=\sqrt[6]{4^6}=4](https://tex.z-dn.net/?f=4%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%2A4%5E%7B%5Cfrac%7B5%7D%7B6%7D%7D%3D%5Csqrt%5B6%5D%7B4%7D%2A%5Csqrt%5B6%5D%7B4%5E5%7D%3D%5Csqrt%5B6%5D%7B4%5E6%7D%3D4 "4^{\frac{1}{6}}*4^{\frac{5}{6}}=\sqrt[6]{4}*\sqrt[6]{4^5}=\sqrt[6]{4^6}=4")
g)![((81)^\frac{1}{2})^{\frac{1}{2}}=81^{\frac{1}{2}*\frac{1}{2}}=81^{\frac{1}{4}}=\sqrt[4]{81}=\sqrt[4]{3^4}=3](https://tex.z-dn.net/?f=%28%2881%29%5E%5Cfrac%7B1%7D%7B2%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B81%7D%3D%5Csqrt%5B4%5D%7B3%5E4%7D%3D3 "((81)^\frac{1}{2})^{\frac{1}{2}}=81^{\frac{1}{2}*\frac{1}{2}}=81^{\frac{1}{4}}=\sqrt[4]{81}=\sqrt[4]{3^4}=3")
h)![(\frac{125}{27})^{-\frac{2}{3}}=(\frac{27}{125})^{\frac{2}{3}}=\sqrt[3]{(\frac{27}{125})^2}=(\frac{3}{5})^2=\frac{9}{25}](https://tex.z-dn.net/?f=%28%5Cfrac%7B125%7D%7B27%7D%29%5E%7B-%5Cfrac%7B2%7D%7B3%7D%7D%3D%28%5Cfrac%7B27%7D%7B125%7D%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B27%7D%7B125%7D%29%5E2%7D%3D%28%5Cfrac%7B3%7D%7B5%7D%29%5E2%3D%5Cfrac%7B9%7D%7B25%7D "(\frac{125}{27})^{-\frac{2}{3}}=(\frac{27}{125})^{\frac{2}{3}}=\sqrt[3]{(\frac{27}{125})^2}=(\frac{3}{5})^2=\frac{9}{25}")
i)![(27^{\frac{1}{2}})^{\frac{2}{3}}=27^{\frac{1}{2}*\frac{2}{3}}=27^{\frac{2}{6}}=27^{\frac{1}{3}}=\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%2827%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D27%5E%7B%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B2%7D%7B3%7D%7D%3D27%5E%7B%5Cfrac%7B2%7D%7B6%7D%7D%3D27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B27%7D%3D3 "(27^{\frac{1}{2}})^{\frac{2}{3}}=27^{\frac{1}{2}*\frac{2}{3}}=27^{\frac{2}{6}}=27^{\frac{1}{3}}=\sqrt[3]{27}=3")
j)![(\frac{1000}{27})^{-\frac{2}{3}}=(\frac{27}{1000})^\frac{2}{3}=\sqrt[3]{(\frac{27}{1000})^2}=(\frac{3}{10})^2=\frac{9}{100}](https://tex.z-dn.net/?f=%28%5Cfrac%7B1000%7D%7B27%7D%29%5E%7B-%5Cfrac%7B2%7D%7B3%7D%7D%3D%28%5Cfrac%7B27%7D%7B1000%7D%29%5E%5Cfrac%7B2%7D%7B3%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B27%7D%7B1000%7D%29%5E2%7D%3D%28%5Cfrac%7B3%7D%7B10%7D%29%5E2%3D%5Cfrac%7B9%7D%7B100%7D "(\frac{1000}{27})^{-\frac{2}{3}}=(\frac{27}{1000})^\frac{2}{3}=\sqrt[3]{(\frac{27}{1000})^2}=(\frac{3}{10})^2=\frac{9}{100}")
k)![27^{\frac{1}{3}}=\sqrt[3]{27}=\sqrt[3]{3^3}=3](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B27%7D%3D%5Csqrt%5B3%5D%7B3%5E3%7D%3D3 "27^{\frac{1}{3}}=\sqrt[3]{27}=\sqrt[3]{3^3}=3")
l)
ł)![81^{\frac{1}{4}}=\sqrt[4]{81}=\sqrt[4]{3^4}=3](https://tex.z-dn.net/?f=81%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B81%7D%3D%5Csqrt%5B4%5D%7B3%5E4%7D%3D3 "81^{\frac{1}{4}}=\sqrt[4]{81}=\sqrt[4]{3^4}=3")
m)
n)![3^{\frac{1}{4}}*27^{\frac{1}{4}}=\sqrt[4]{3}*\sqrt[4]{27}=\sqrt[4]{3}*\sqrt[4]{3^3}=\sqrt[4]{3^4}=3](https://tex.z-dn.net/?f=3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%2A27%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B3%7D%2A%5Csqrt%5B4%5D%7B27%7D%3D%5Csqrt%5B4%5D%7B3%7D%2A%5Csqrt%5B4%5D%7B3%5E3%7D%3D%5Csqrt%5B4%5D%7B3%5E4%7D%3D3 "3^{\frac{1}{4}}*27^{\frac{1}{4}}=\sqrt[4]{3}*\sqrt[4]{27}=\sqrt[4]{3}*\sqrt[4]{3^3}=\sqrt[4]{3^4}=3")
ń)![5^{\frac{2}{3}}*5^{\frac{1}{3}}=\sqrt[3]{5^2}*\sqrt[3]5=5](https://tex.z-dn.net/?f=5%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2A5%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B5%5E2%7D%2A%5Csqrt%5B3%5D5%3D5 "5^{\frac{2}{3}}*5^{\frac{1}{3}}=\sqrt[3]{5^2}*\sqrt[3]5=5")
o)![3^{\frac{1}{3}}*9^{\frac{1}{3}}=\sqrt[3]3*\sqrt[3]9=\sqrt[3]{3*3^2}=\sqrt[3]{3^3}=3](https://tex.z-dn.net/?f=3%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%2A9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D3%2A%5Csqrt%5B3%5D9%3D%5Csqrt%5B3%5D%7B3%2A3%5E2%7D%3D%5Csqrt%5B3%5D%7B3%5E3%7D%3D3 "3^{\frac{1}{3}}*9^{\frac{1}{3}}=\sqrt[3]3*\sqrt[3]9=\sqrt[3]{3*3^2}=\sqrt[3]{3^3}=3")
ó)![6^{\frac{3}{4}}*6^{\frac{1}{4}}=\sqrt[4]{6^3}*\sqrt[4]6=\sqrt[4]{6^4}=6](https://tex.z-dn.net/?f=6%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%2A6%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B6%5E3%7D%2A%5Csqrt%5B4%5D6%3D%5Csqrt%5B4%5D%7B6%5E4%7D%3D6 "6^{\frac{3}{4}}*6^{\frac{1}{4}}=\sqrt[4]{6^3}*\sqrt[4]6=\sqrt[4]{6^4}=6")
p)![(64^{\frac{1}{2}})^\frac{1}{3}=64^{\frac{1}{2}*\frac{1}{3}}=64^{\frac{1}{6}}=\sqrt[6]{64}=\sqrt[6]{2^6}=2](https://tex.z-dn.net/?f=%2864%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%5E%5Cfrac%7B1%7D%7B3%7D%3D64%5E%7B%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B3%7D%7D%3D64%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%3D%5Csqrt%5B6%5D%7B64%7D%3D%5Csqrt%5B6%5D%7B2%5E6%7D%3D2 "(64^{\frac{1}{2}})^\frac{1}{3}=64^{\frac{1}{2}*\frac{1}{3}}=64^{\frac{1}{6}}=\sqrt[6]{64}=\sqrt[6]{2^6}=2")
r)![(\frac{8}{1000})^{-\frac{2}{3}}=(\frac{1000}{8})^{\frac{2}{3}}=\sqrt[3]{(\frac{1000}{8})^2}=\sqrt[3]{(\frac{10^3}{2^3})}^2=(\frac{10}{2})^2=5^2=25](https://tex.z-dn.net/?f=%28%5Cfrac%7B8%7D%7B1000%7D%29%5E%7B-%5Cfrac%7B2%7D%7B3%7D%7D%3D%28%5Cfrac%7B1000%7D%7B8%7D%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B1000%7D%7B8%7D%29%5E2%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B10%5E3%7D%7B2%5E3%7D%29%7D%5E2%3D%28%5Cfrac%7B10%7D%7B2%7D%29%5E2%3D5%5E2%3D25 "(\frac{8}{1000})^{-\frac{2}{3}}=(\frac{1000}{8})^{\frac{2}{3}}=\sqrt[3]{(\frac{1000}{8})^2}=\sqrt[3]{(\frac{10^3}{2^3})}^2=(\frac{10}{2})^2=5^2=25")
s)![(32^{\frac{1}{2}})^\frac{2}{5}=32^{\frac{1}{2}*\frac{2}{5}}=32^{\frac{2}{10}}=32^{\frac{1}{5}}=\sqrt[5]{32}=\sqrt[5]{2^5}=2](https://tex.z-dn.net/?f=%2832%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%5E%5Cfrac%7B2%7D%7B5%7D%3D32%5E%7B%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B2%7D%7B5%7D%7D%3D32%5E%7B%5Cfrac%7B2%7D%7B10%7D%7D%3D32%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%3D%5Csqrt%5B5%5D%7B32%7D%3D%5Csqrt%5B5%5D%7B2%5E5%7D%3D2 "(32^{\frac{1}{2}})^\frac{2}{5}=32^{\frac{1}{2}*\frac{2}{5}}=32^{\frac{2}{10}}=32^{\frac{1}{5}}=\sqrt[5]{32}=\sqrt[5]{2^5}=2")
ś)![(\frac{8}{125})^{-\frac{2}{3}}=(\frac{125}{8})^{\frac{2}{3}}=\sqrt[3]{(\frac{125}{8})^2}=\sqrt[3]{(\frac{5^3}{2^3})^2}=(\frac{5}{2})^2=\frac{25}{4}=6\frac{1}{4}](https://tex.z-dn.net/?f=%28%5Cfrac%7B8%7D%7B125%7D%29%5E%7B-%5Cfrac%7B2%7D%7B3%7D%7D%3D%28%5Cfrac%7B125%7D%7B8%7D%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B125%7D%7B8%7D%29%5E2%7D%3D%5Csqrt%5B3%5D%7B%28%5Cfrac%7B5%5E3%7D%7B2%5E3%7D%29%5E2%7D%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E2%3D%5Cfrac%7B25%7D%7B4%7D%3D6%5Cfrac%7B1%7D%7B4%7D "(\frac{8}{125})^{-\frac{2}{3}}=(\frac{125}{8})^{\frac{2}{3}}=\sqrt[3]{(\frac{125}{8})^2}=\sqrt[3]{(\frac{5^3}{2^3})^2}=(\frac{5}{2})^2=\frac{25}{4}=6\frac{1}{4}")
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