Odpowiedź:
9.
a = 3
[tex]\frac{h}{6} = tg 30^o = \frac{\sqrt{3}} {3}[/tex]
więc h = 2√3
V = Pp* h = 6*[tex]\frac{a^2*\sqrt{3} }{4} *h = 1,5* 3^2*\sqrt{3}* 2\sqrt{3} = 81[/tex] j²
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10.
Pb = 3 Pp
a = 4 cm
4*0,5* a*[tex]h_b = 3 a^2[/tex] / : 2 a
[tex]h_b = 1,5 a = 1,5* 4 cm = 6 cm[/tex]
h² + ( 0,5 a)² = h_b^2
h² = 6² - 2² = 36 - 4 = 32 = 16*2
h = 4 √2
----------------
V = [tex]\frac{1}{3} *Pp*h = \frac{1}{3} *4^2*4\sqrt{2} = \frac{64 \sqrt{2} }{3}[/tex]
V = [tex]\frac{64 \sqrt{2} }{3}[/tex] cm³
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Verified answer
Odpowiedź:
9.
a = 3
[tex]\frac{h}{6} = tg 30^o = \frac{\sqrt{3}} {3}[/tex]
więc h = 2√3
V = Pp* h = 6*[tex]\frac{a^2*\sqrt{3} }{4} *h = 1,5* 3^2*\sqrt{3}* 2\sqrt{3} = 81[/tex] j²
=============================================
10.
Pb = 3 Pp
a = 4 cm
4*0,5* a*[tex]h_b = 3 a^2[/tex] / : 2 a
[tex]h_b = 1,5 a = 1,5* 4 cm = 6 cm[/tex]
h² + ( 0,5 a)² = h_b^2
h² = 6² - 2² = 36 - 4 = 32 = 16*2
h = 4 √2
----------------
V = [tex]\frac{1}{3} *Pp*h = \frac{1}{3} *4^2*4\sqrt{2} = \frac{64 \sqrt{2} }{3}[/tex]
V = [tex]\frac{64 \sqrt{2} }{3}[/tex] cm³
===============
Szczegółowe wyjaśnienie: