Proszę o obliczenie(układ równań) i możlwe wytłumaczenie: {240=v*t {240=(v+20)*(t-1)
v*t = 240 => t = 240/v
( v + 20)*( t - 1) = 240
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t = 240/v
v*t - v + 20 t - 20 = 240
240 - v + 20*[ 240/ v] - 20 = 240
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- v + 4800/v - 20 = 0 / * v
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- v^2 + 4 800 - 20 v = 0
v^2 + 20 v - 4 800 = 0
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delta = 20^2 - 4*1*( -4800) = 400 + 19 200 = 19 600
p (delty) = 140
v = [ - 20 + 140]/2 = 120/2 = 60
oraz
t = 240 /60 = 4
Odp. v = 60 km/h, t = 4 h.
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v*t = 240 => t = 240/v
( v + 20)*( t - 1) = 240
-------------------------------
t = 240/v
v*t - v + 20 t - 20 = 240
-------------------------------
t = 240/v
240 - v + 20*[ 240/ v] - 20 = 240
------------------------------------------
t = 240/v
- v + 4800/v - 20 = 0 / * v
-----------------------------
t = 240/v
- v^2 + 4 800 - 20 v = 0
-------------------------------
t = 240/v
v^2 + 20 v - 4 800 = 0
------------------------------
delta = 20^2 - 4*1*( -4800) = 400 + 19 200 = 19 600
p (delty) = 140
v = [ - 20 + 140]/2 = 120/2 = 60
oraz
t = 240 /60 = 4
Odp. v = 60 km/h, t = 4 h.
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