Proszę o dokładne rozwiązanie :)
a) [(1+2)]
b)
Z góry dziękuję :) Za najlepsze rozwiązanie daję naj : )
a) 1+2=
1+2[(1+1/2)⁻¹-1]⁻¹ * [(1+1/2)⁻¹-1]⁻¹=1+2[(3/2)⁻¹-1]⁻¹ * [(3/2)⁻¹-1]⁻¹=1+2(2/3-1)⁻¹ * (2/3-1)⁻¹=1+2(-1/3)⁻¹ * (-1/3)⁻¹=1+2(-3) * (-3)=1+18=19
b) =
[(1+1/3)⁻¹-2]⁻¹ * [(1+1/3)⁻¹-2]⁻¹=[(4/3)⁻¹-2]⁻¹ * [(4/3)⁻¹-2]⁻¹=(3/4-2)⁻¹ * (3/4-2)⁻¹=(3/4-2)⁻¹ * (3/4-2)⁻¹=(-5/4)⁻¹ * (-5/4)¹= (-4/5) * (-4/5)= 16/25
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a) 1+2=
1+2[(1+1/2)⁻¹-1]⁻¹ * [(1+1/2)⁻¹-1]⁻¹=1+2[(3/2)⁻¹-1]⁻¹ * [(3/2)⁻¹-1]⁻¹=1+2(2/3-1)⁻¹ * (2/3-1)⁻¹=1+2(-1/3)⁻¹ * (-1/3)⁻¹=1+2(-3) * (-3)=1+18=19
b) =
[(1+1/3)⁻¹-2]⁻¹ * [(1+1/3)⁻¹-2]⁻¹=[(4/3)⁻¹-2]⁻¹ * [(4/3)⁻¹-2]⁻¹=(3/4-2)⁻¹ * (3/4-2)⁻¹=(3/4-2)⁻¹ * (3/4-2)⁻¹=(-5/4)⁻¹ * (-5/4)¹= (-4/5) * (-4/5)= 16/25