Proszę o dokładne obliczenia..pierwiastki i potegizad1zad2zad 3.... Question from @Xalusiax445

December 2018 1 75 Report

Proszę o dokładne obliczenia..pierwiastki i potegi
zad1
$\sqrt[3]{(-8):1} =$

$\sqrt[3]{64:8} =$

$\sqrt[3]{216:64}$

$\sqrt{ \frac{25}{36} }$

$\sqrt{5 \frac{4}{9} } =$

$\sqrt[3]{ \frac{8}{27} } =$

zad2

$\sqrt{2*} \sqrt{8} =$

$\sqrt{3} * \sqrt{12} =$

$\sqrt{32} * \sqrt{2} =$

$\sqrt{20} * \sqrt{5} =$

$\sqrt{128} * \sqrt{0,5} =$

$\sqrt{ \frac{2}{5} } * \sqrt 1{ \frac{1}{9} } =$

$\sqrt[3]{(-9)} * \sqrt[3]{3}$

$\sqrt[3]{4} * \sqrt[3]{2} =$

$\sqrt[3]{25} * \sqrt[3]{5} =$

zad 3

$\sqrt{50} : \sqrt{2} =$

$\sqrt{48} : \sqrt{3} =$

$\sqrt{125} : \sqrt{5} =$

$\sqrt[3]{32} : \sqrt[3]{4} =$

$\sqrt[3]{54} : \sqrt[3]{2}$

$\sqrt[3]{27} : \sqrt[3]{(-9)} =$

$\sqrt[3]{ \frac{2}{9} } : \sqrt[3]{ \frac{3}{4} } =$

$\sqrt{ \frac{2}{9} } : \sqrt{ \frac{8}{9} } =$

$\sqrt[3]{ \frac{2}{3} } : \sqrt[3]{ \frac{2}{81} }$

krysta $zad.1)\\\\\sqrt[3]{(-8):1} =\sqrt[3]{(-8) }=\sqrt[3]{(-2)^3 } = -2\\\\\sqrt[3]{64:8} =\sqrt[3]{8}=\sqrt[3]{2^3}=2\\\\\sqrt[3]{216:64}=\sqrt[3]{216:64}=\sqrt[3]{216:64}=\sqrt[3]{(\frac{6}{4})^3}\frac{6}{4}\\\\\sqrt{ \frac{25}{36} }=\sqrt{ \frac{ 5^2}{ 6^2} }=\frac{5}{6}\\\\\sqrt{5 \frac{4}{9} } =\sqrt{ \frac{49}{9} }=\sqrt({ \frac{ 7}{3} )^2} =\frac{7}{3}\\\\\sqrt[3]{ \frac{8}{27} } =\sqrt[3]{( \frac{2}{3})^3 }=\frac{2}{3}$

$zad2)\\\\\sqrt{2 } *\sqrt{8} =\sqrt{2*8}= \sqrt{16}=4\\\\\sqrt{3} * \sqrt{12} =\sqrt{3*12}=\sqrt{36}=6\\\\\sqrt{32} * \sqrt{2} =\sqrt{32*2}=\sqrt{64}=8\\\\\sqrt{20} * \sqrt{5} =\sqrt{20*5}=\sqrt{100}=10\\\\\sqrt{128} * \sqrt{0,5} =\sqrt{128*0,5}=\sqrt{64}=8\\\\\sqrt{ \frac{2}{5} } * \sqrt 1{ \frac{1}{9} } =\sqrt{ \frac{2}{5} } * \sqrt { \frac{10}{9} } =\sqrt{\frac{2}{5}*\frac{10}{9}}=\sqrt{\frac{4}{9}}=\frac{2}{3}$

$\sqrt[3]{(-9)} * \sqrt[3]{3}= \sqrt[3]{-9*3}=\sqrt[3]{-27}=-3\\\\\sqrt[3]{4} * \sqrt[3]{2}=\sqrt[3]{4*2}=\sqrt[3]{8}=2\\\\\sqrt[3]{25} * \sqrt[3]{5} =\sqrt[3]{25*5}=\sqrt[3]{125}=5$

$zad 3)\\\\\sqrt{50} : \sqrt{2} =\sqrt{50:2}=\sqrt{25}=5\\\\\sqrt{48} : \sqrt{3} =\sqrt{48:3}=\sqrt{16}=4\\\\\sqrt{125} : \sqrt{5} =\sqrt{125:5}=\sqrt{25}=5 \\\\\sqrt[3]{32} : \sqrt[3]{4} =\sqrt[3]{32:4}=\sqrt[3]{8}=2$

$\sqrt[3]{54} : \sqrt[3]{2}=\sqrt[3]{54:2}=\sqrt[3]{27}=3\\\\\sqrt[3]{27} : \sqrt[3]{(-9)} =\sqrt[3]{27: (-9)}=\sqrt[3]{-3}\\\\ \sqrt[3]{ \frac{2}{9} } : \sqrt[3]{ \frac{3}{4} } =\sqrt[3]{ \frac{2}{9} :\frac{3}{4}}=\sqrt[3]{ \frac{2}{9}*\frac{4}{3}}= \sqrt[3]{\frac{8}{27}}=\frac{2}{3}$

$\sqrt{ \frac{2}{9} } : \sqrt{ \frac{8}{9} } =\sqrt{ \frac{2}{9}: \frac{8}{9}} =\sqrt{ \frac{2}{9}* \frac{9}{8}} =\sqrt{\frac{1}{4}}=\frac{1}{2} \\\\ \sqrt[3]{ \frac{2}{3} } : \sqrt[3]{ \frac{2}{81} }=\sqrt[3]{ \frac{2}{3}: \frac{2}{81}} =\sqrt[3]{ \frac{2}{3}* \frac{81}{2}} = \sqrt[3]{27 } =3$

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