Question

Proszę na jutro bardzo potrzebuje!!!!

Answer 1

zad. 1

x/4 - 5-x/6 2/3

3x - 2(5-x) 8

3x - 10 + 2x 8

5x - 10 8

5x 8 + 10

5x 18

x 18/5

zad.2

a) (x+1)*(8x-3) = (4x-3)*(2x+1)

8x^2 - 3x + 8x - 3 = 8^2 + 4x - 6x - 3

-3x + 8x = 4x - 6x

5x = -2x

5x + 2x = 0

7x = 0 /:7

x = 0

b) 4(x+6)-(4x^2+6)=(3-0,5x)*(8x-2)

4x + 24 - 4x^2 - 6 = 24x - 6 - 4^2 + x

4x + 24 = 24x + x

4x + 25 = 25x

4x - 25x = -24

-21x = -24 /:-21

x = 8/7

zad 3

(√3+√27)^2 = (√3 + 3√3)^2 = (4√3)^2 = 16 * 3 = 48

(3√2-√6)^2 = 18 - 6√12 + 6 = 18 - 12√3 + 6 = 24 - 12√

(√10-√2)*(√10+√2) = 10-2 = 8

zad 4

(√3x - 2)^2 > 3x^2 - 2

3x^2 - 4√3 + 4 > 3x^3 - 2

-4√3x + 4 > -2

-4√3x > -2-4

-4√3x > -6

x < 3/2√3

x < √3/2

zad 6

a) (x + 3)* (x-3) - (x+4)^2 + (5x-1)^2

x^2 - 9 - (x^2 + 8x + 16) + 25x^2 -10x + 1

x^2 - 9 - x^2 - 8x - 16 + 25x^2 - 10x + 1

-24 - 18x + 25x^2

25x^2 - 18x -24

b) -(-3x-5)^2-(-x-6)^2

-(9x^2 + 30x + 25) - (x^2 + 12x + 36)

-9x^2 - 30x - 25 - x^2 - 12x -36

-10x^2 - 42x - 61