Question

Prosty układ równań, prosze o pomoc:
2^x * 3^y = 648
3^x * 2^y = 432

Answer 1

2^x * 3^y = 648
3^x * 2^y = 432
--------------------podziel stronami
(2/3)^x *(3/2)^y=3/2
(2/3)^x*(2/3)^-y=3/2
(2/3)^x-y=2/3^-1
   x-y=-1
x=y-1
podstaw do
3^x * 2^y = 432
3^(y-1) *2^y=432
1/3 *3^y*2^y=432  /*3
     6^y=1296
     6^y=6^4
       y=4
x=y-1=4-1=3
odp x=3 y=4