Prostokat - obwod 48dm jeden z bokow 6dm . Oblicz pole !
O=48 dm; a=6 dm, b=?
2a+2b=48
2*6+2b=48
12+2b=48
2b=48-12
2b=36/2
b=18
P=a*b
P=6 dm*18 dm
P=108 dm^2- pole
Dane:
Obw=48dm
a=6dm
Szukane:
P=?
Obl:
Obw=2a+2b | -2a
2b=Obw-2a | /2
b=Obw-2a/2
P=ab
P=a*Obw-2a/2=6dm*(48dm-6dm*2/2)=6*(36/2)=6*18=108[dm²]=1,08m²
Odp: Pole tego prostokąta wynosi 1,08m².
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O=48 dm; a=6 dm, b=?
2a+2b=48
2*6+2b=48
12+2b=48
2b=48-12
2b=36/2
b=18
P=a*b
P=6 dm*18 dm
P=108 dm^2- pole
Dane:
Obw=48dm
a=6dm
Szukane:
P=?
Obl:
Obw=2a+2b | -2a
2b=Obw-2a | /2
b=Obw-2a/2
P=ab
P=a*Obw-2a/2=6dm*(48dm-6dm*2/2)=6*(36/2)=6*18=108[dm²]=1,08m²
Odp: Pole tego prostokąta wynosi 1,08m².