prostakąt o polu P można rociąc na dwa kwadraty.oblicz obwód tego prostokata.
a)P=98cm^{2}
b)P=
c)P=
d)P=
P1 - pole kwadratu
a - długość boku kwadratu
L - obwód prostokąta
a) P1 = P : 2 = 98 cm² : 2 = 49 cm²
a = √49 cm = 7 cm
L = 2 ( 2a + a) = 2*3a = 6a = 6* 7 cm = 42 cm
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b) P1 = P : 2 = 6,48 cm² : 2 = 3,24 cm²
a = √3,24 cm = 1,8 cm
L = 6a = 6*1,8 cm = 10,8 cm
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c) P1 = P : 2 = (1/8) m² : 2 = (1/4) m²
a = √(1/4) m = (1/2) m
L = 6a = 6*(1/2) m = 3 m
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d) P1 = P : 2 = (1/72) m² : 2 = (1/144) m²
a = √(1/144) m = (1/12) m
L = 6*a = 6* (1/12) m = (6/12) m = (1/2) m = 0,5 m
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P1 - pole kwadratu
a - długość boku kwadratu
L - obwód prostokąta
a) P1 = P : 2 = 98 cm² : 2 = 49 cm²
a = √49 cm = 7 cm
L = 2 ( 2a + a) = 2*3a = 6a = 6* 7 cm = 42 cm
-----------------------------------------------------
b) P1 = P : 2 = 6,48 cm² : 2 = 3,24 cm²
a = √3,24 cm = 1,8 cm
L = 6a = 6*1,8 cm = 10,8 cm
------------------------------------------------------
c) P1 = P : 2 = (1/8) m² : 2 = (1/4) m²
a = √(1/4) m = (1/2) m
L = 6a = 6*(1/2) m = 3 m
-------------------------------------------------------
d) P1 = P : 2 = (1/72) m² : 2 = (1/144) m²
a = √(1/144) m = (1/12) m
L = 6*a = 6* (1/12) m = (6/12) m = (1/2) m = 0,5 m
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