" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
v=πr²h=200πcm³/:π
h=200:5²
h=200:25
h=8cm = wysokość walca
pole=2πr²+2πrh=2π×5²+2π×5×8=50π+80π=130πcm²
V= 200pi cm ²
V= pi r ² * h
200pi= pi 25 *h /:pi
200= 25 h /: 25
h=8
2 pi r²+ pi rh=
=2 pi *5²+2 pi*5*8=
=50 pi +80 pi =130 pi cm²
h= ?
Pc= ?
1.Obliczamy H
V= πr²* h
h= v/πr²
h= 200π/ 5²π
h= 200π/ 25π
h= 8π
2. Obliczamy Pc
Pc= 2πr² + 2πr* h
Pc+ 2 * 25π + 2*5π *8
Pc= 50π + 80π
Pc= 130π