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CuSO₄ · xH₂O ---Temp.--> CuSO₄ + xH₂O
Z 50 g hydratu otrzymaliśmy 32 g soli bezwodnej
x g hydratu stanowi 159,61 g soli bezwodnej
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x = (159,61 · 50) ÷ 32 = 249,39 g
249,39 - 159,61 = 89,78 g
M(H₂O) = 18 g/mol
89,78 ÷ 18 ≈ 5
Zatem wzór hydratu to: CuSO₄ · 5H₂O