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Lartan 2: pH = 2 ⇒ [H+] = 0,01 M ⇒ V2 = 100 ml
[H+] campuran =( M1xV1 + M2xV2)/(V1 + V2)
=(0,1 x 400 + 0,01 x 100)/(400 + 100)
=(40 + 1)/500
= 41/500
= 0,082
pH = -log 0,082
= 3 - log 82