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2πr=obwód podstawy
1 opcja;
jesli H=12cm
2πr=8cm, to;
2πr=8 /;2π
r=4/π
Pp=πr²=π*(4/π)²=16/π
v=PpH=16/π*12=192/π cm³
Pb=12*8=96
Pc=2*16/π+96=32/π +96 cm²
2opcja;
H=8cm
2πr=12cm /;2π
r=6/π
Pp=π*(6/π)²=36/π
Pc=2*36/π+96=72/π+96 cm²
v=36/π*8=288/πcm³