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H=10
2πR=50→R=25/π
tgα=H/(2R)=10/(50/π)=0,2π=0.62831853
α=32.14°
2 przypadek
H=50
2πR=10→R=5/π
tgα=H/(2R)=50/(10/π)=5π=15.70796325
α=86.36°
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Hans