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α:360×2πr=150:360×2π×24=20π
obliczam r podstawy
2πr=20π/:π
2r=20
r=20:2
r=10cm
obliczam h :
h²=24²-10²
h²=576-100
h=√476
h=2√119cm
v=⅓πr²h=⅓π×10²×2√119=66⅔√119 πcm³
pole boczne=πrl=π×10×24=240πcm²