Question

potrzebuje rozwiazania tych oytan jak najszybciej

Answer 1

zad 11

[tex]\sqrt{3\frac{1}{16}} = \sqrt{\frac{49}{16} } = \frac{7}{4} = 1\frac{3}{4}[/tex]

zad 12

[tex]\sqrt{4 * 9} = 2 * 3 = 6[/tex]

zad 13

[tex](\sqrt[3]{2} )^{9} = 2^{6} = 64[/tex]

zad 14

[tex]\sqrt{7} * 5\sqrt{7} = 6\sqrt{7}[/tex]

zad 15

a) [tex]\sqrt{20} + \sqrt{45} - 2\sqrt{5} = \sqrt{4*5} + \sqrt{9*5} - 2\sqrt{5} = 2\sqrt{5} +3\sqrt{5} - 2\sqrt{5} = 3\sqrt{5}[/tex]

b) [tex]3\sqrt{24} - \sqrt{150} + 4\sqrt{54} = 3\sqrt{4*6} - \sqrt{25*6} +4\sqrt{9*6} =6\sqrt{6} -5\sqrt{6} + 12\sqrt{6} = 13\sqrt{6}[/tex]

c) [tex]5\sqrt{27} +\sqrt{75} -2\sqrt{12} = 5\sqrt{9*3} + \sqrt{25*3} +2\sqrt{4*3} = 15\sqrt{3} +5\sqrt{3} +4\sqrt{3} = 24\sqrt{3}[/tex]

d) [tex]\frac{1}{2} \sqrt{8} +\frac{3}{4} \sqrt{32} - 2\sqrt{50} = \frac{1}{2} \sqrt{4*2} +\frac{3}{4} \sqrt{16*2} -2\sqrt{25*2} =\frac{1}{2}*2 \sqrt{2} +\frac{3}{4} *4\sqrt{2} -10\sqrt{2} =\sqrt{2} +3\sqrt{2} -10\sqrt{2} =-6\sqrt{2}[/tex]

Mam nadzieję, że pomogłam ^_^