Odpowiedź:
Niech I AB I = 4 a I BC I = 4 b
Pole ABCD
P = 4 a*4b = 16 a*b
PΔ = 16 a*b - 0,5*2a*2 b - 0,5*2 a*3 b - 0,5*(2 b + b)*4 a =
= 16 a*b - 2 a*b - 3 a*b - 6 a*b = 16 a*b - 11 a*b = 5 a*b
PΔ : P = [tex]\frac{5}{16} = 31,25[/tex] %
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Szczegółowe wyjaśnienie:
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Odpowiedź:
Niech I AB I = 4 a I BC I = 4 b
Pole ABCD
P = 4 a*4b = 16 a*b
PΔ = 16 a*b - 0,5*2a*2 b - 0,5*2 a*3 b - 0,5*(2 b + b)*4 a =
= 16 a*b - 2 a*b - 3 a*b - 6 a*b = 16 a*b - 11 a*b = 5 a*b
PΔ : P = [tex]\frac{5}{16} = 31,25[/tex] %
===========================
Szczegółowe wyjaśnienie: