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l = 2r + 3 = tworząca stożka
Ob = 2l + 2r = 36
2(2r + 3) + 2r = 36
6r = 30
r = 5 = promień podstawy stożka
l = 2r + 3 = 13
Pc = πr² + πrl = πr(r + l) = 5π(5+13) = 90π [cm3]
V = 1/3 πr²h
h = √(l²-r²)= √(169-25) = 12
V = 1/3 π*5²*12 = 100π
Odp. Pc = 90π, V = 100π [cm3]