Potrzebuje najszybciej jak to mozliwe rozwiazanie tego rownania:
3(x-2)² = 48
Z gory dziekuje ;)
3(x-2)²-48=0/:3
(x-2)²-16=0
(x-2-4)(x-2+4)=0
(x-6)(x+2)=0
x=6 v x=-2
3(x-2)²=48
3(x²-4x+4)=48
3x²-12x+12=48
3x²-12x-36=0
x²-4x-12=0
a=1
b=-4
c=-12
Δ=b²-4ac
Δ=(-4)²-4·1·(-12)=16+48=64
√Δ=8
x₁=8-(-4)/2=6
x₂=-8+4/2=-2
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3(x-2)²-48=0/:3
(x-2)²-16=0
(x-2-4)(x-2+4)=0
(x-6)(x+2)=0
x=6 v x=-2
3(x-2)²=48
3(x²-4x+4)=48
3x²-12x+12=48
3x²-12x-36=0
x²-4x-12=0
a=1
b=-4
c=-12
Δ=b²-4ac
Δ=(-4)²-4·1·(-12)=16+48=64
√Δ=8
x₁=8-(-4)/2=6
x₂=-8+4/2=-2