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2.[(x-1)(x+1)]/[(x-1)³]=(x+1)/(x-1)²
3. [(x²-y²)³]/[(x²-y²)²]=x²-y²
a² - 4ab + 4b² (a - 2b)² (a - 2b)² (a - 2b)
_____________ = ________ = _______________ = _________
a² - 4b² a² - (2b)² (a - 2b) (a + 2b) (a + 2b)
x² - 1 x² - 1² (x - 1) (x + 1) (x + 1)
______________ = ____________ = _______________ = ________
x³ - 3x² + 3x - 1 (x - 1)³ (x - 1)³ (x - 1)²
(x³ - y³) (x + y) (x - y) (x² + xy + y²) (x + y)
______________ = _________________________ =
(x² - y²)² (x² - y²)²
(x - y) (x + y) (x² + xy + y²) (x² - y²) (x² + xy + y²)
=__________________________ = _____________________ =
(x² - y²)² (x² - y²)²
(x² + xy + y²)
= ______________
(x² - y²)
Ehhh widzę, że chyba się nie doczytasz, sorki