Potrzebuję pomocy i proszę o nią. Oblicz: 64 do potęgi jednej czwartej - 3 pierwiastki z dwóch
(64¹/⁴ - 3√2)[2³/² + (1/9 · 1/2)⁻¹/²] =
= (⁴√64 - 3√2)[2³/² + (9·2)¹/²] =
= (⁴√2⁶ - 3√2)(2³/² + √9·√2] =
= (2³/² - 3√2)(2³/² + 3√2) =
= (2³/²)² - (3√2)² =
= 2³ - 9·2 =
= 8 - 18
= -10
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(64¹/⁴ - 3√2)[2³/² + (1/9 · 1/2)⁻¹/²] =
= (⁴√64 - 3√2)[2³/² + (9·2)¹/²] =
= (⁴√2⁶ - 3√2)(2³/² + √9·√2] =
= (2³/² - 3√2)(2³/² + 3√2) =
= (2³/²)² - (3√2)² =
= 2³ - 9·2 =
= 8 - 18
= -10