Potrzebuję na chemię ;) oblicz ile gramów kwasu siarkowego (VI) znajduje się w 0,5 dm^3 roztworu 60% 0,5 to jest Vr
ms=? Vr=0,5dm3=500cm3 Cp=60%
d=1,5g/cm3
d=m/V
mr=d*V
mr=1,5g/cm3*500cm3
mr=750g
ms=mr*Cp/100%
ms=750g*60%/100%
ms=450g
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ms=? Vr=0,5dm3=500cm3 Cp=60%
d=1,5g/cm3
d=m/V
mr=d*V
mr=1,5g/cm3*500cm3
mr=750g
ms=mr*Cp/100%
ms=750g*60%/100%
ms=450g