Question

POTĘGOWANIE.Zadanie w załączniku prosze rozwiązać zadania:Ćw 1 str.34, Ćw 3 str.35,Zad 1 str 36.Daje najj , spam zgłaszam odrazu.Proszę o szybką odpowiedz.

Answer 1

1/34

 

a)

9^2 = 9 * 9 = 81

9^3 = 9 * 9 * 9 = 729

9^4 = 9 * 9 * 9 * 9 = 5861

 

b)

(3/4)^2 = 9/16

(3/4)^3 = 27/64

(3/4)^4 = 81/256

 

c)

(-2/5)^2 = -4/25

(-2/5)^3 = -8/125

(-2/5)^4 = -16/625

 

3/35

 

a) 4^-2 = (1/4)^2 = 1/16

b) 4^-3 = (1/4)^3 = 1/64

c) (-3)^-2 = (-1/3)^2 = -1/9

d) (-3)^-3 = (-1/3)^3 = -1/27

e) (1/2)^-2 = 2^2 = 4

f) (1/2)^-5 = 2^5 = 32

g) (2/3)^-2 = (3/2)^2 = 9/4 = 2 1/4

h) (-2/3)^-4 = (-3/2)^4 = -81/16 = -5 1/16

i) (0,2)^-2 = (1/5)^-2 = 5^2 = 25

j) (-0,2)^-3 = (-1/5)^-3 = (-5)^3 = (-125)

 

1/36

 

a)

(-2)^5 = -32

(-2)^-5 = (-1/2)^5 = -1/32

2^-5 = (1/2)^5 = 1/32

 

b)

(1/3)^-2 = 3^2 = 9

(-1/3)^-2 = -3^2 = 9

(-1/3)^-3 = -3^3 = -27

Answer 2

Ćwiczenie 2 str. 34
(-3)^{9} < (-2)^{9} < (-2)^{4} < (-3)^{4}

 

 

ćw.1 str, 34

a. = 81

9^{3} = 729

9^{4} = 6561

 

b.  

3/4^{3}= 27/64

3/4^{4} = 81/384

 

c. (-2/5)^{2} = 4/25

  (-2/5)^{3} = -8/125

 (-2/5)^{4} = 16/625

 

Ćw. 3. str 35 

w tym zadaniu stosuje się wzór, który masz podany w książce i myślę, że spokojnie jesteś w stanie zrobić to zadanie sam/sama.

a. 4^{-2} = 1/4^{2} = 1/16

b. 4^{-3} = 1/4^{3} = 1/64
c. (-3)^{-2} = 1/(-3)^{2} = 1/9

itd.

 

Zad.1. str. 36

a. -2^{5} = 32
-2^{-5} = 1/(-2)^{5} = 1/-32 = -1/32
2^-{5} = 1/32

b. 1/3^{-2} = 1/ (1/3)^{2} = 1/ (1/9) = 1 * 9 = 9
(-1/3)^{-2} = 9
(-1/3)^{-3} = 1/ (-1/3)^{3} = 1/ (-1/27) = -27

c.

 

d.