potęgi, pierwiastki :D
w załączniku na kartce też proszę robić przykład A) skreślony;P
Zadanie 1.
c)
Zadanie 2.
(-0,02)³ = -0,000008
Zadanie 3.
d) 0,2¹²⁰ * 5¹²⁰ = 1¹²⁰ = 1
e) ((3⁷*3²)² : 3¹⁷)³ = ((3⁹)² :3¹⁷)³ = (3¹⁸:3¹⁷)³ = (3¹)³ = 3³ = 27
f) 2⁵ * 4³ :8³ = 2⁵* (2²)³ : (2³)³ = 2⁵ * 2⁶ : 2⁹ = 2¹¹ : 2⁹ = 2² = 4
Zadanie 4.
(2^x)² = 16
2^x = √16 = 4
I teraz 2 do potęgi której da 4.
Czyli x = 2
zadanie 2.
1.
a)
√1 = 1
√25/49 = 5/7
√2¼ = √9/4 = 3/2 = 1½
√0,01 = 0,1
b)
√289 = 17
√36/121 = 6/11
√4²¹/₂₅ = √¹²¹/₂₅ = 11/5 = 2⅕
√2,89 = 1,7
2.
∛-1 = -1
∛1/27 = ⅓
∛0,008 = 0,2
∛-0,125 = -0,5
∛0 = 0
∛-⅛ = -½
∛0,064 = 0,4
∛2 ¹⁰/₂₇ = ∛64/27 = 4/3 = 1⅓
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Zadanie 1.
c)
Zadanie 2.
(-0,02)³ = -0,000008
Zadanie 3.
d) 0,2¹²⁰ * 5¹²⁰ = 1¹²⁰ = 1
e) ((3⁷*3²)² : 3¹⁷)³ = ((3⁹)² :3¹⁷)³ = (3¹⁸:3¹⁷)³ = (3¹)³ = 3³ = 27
f) 2⁵ * 4³ :8³ = 2⁵* (2²)³ : (2³)³ = 2⁵ * 2⁶ : 2⁹ = 2¹¹ : 2⁹ = 2² = 4
Zadanie 4.
(2^x)² = 16
2^x = √16 = 4
I teraz 2 do potęgi której da 4.
Czyli x = 2
zadanie 2.
1.
a)
√1 = 1
√25/49 = 5/7
√2¼ = √9/4 = 3/2 = 1½
√0,01 = 0,1
b)
√289 = 17
√36/121 = 6/11
√4²¹/₂₅ = √¹²¹/₂₅ = 11/5 = 2⅕
√2,89 = 1,7
2.
a)
∛-1 = -1
∛1/27 = ⅓
∛0,008 = 0,2
∛-0,125 = -0,5
b)
∛0 = 0
∛-⅛ = -½
∛0,064 = 0,4
∛2 ¹⁰/₂₇ = ∛64/27 = 4/3 = 1⅓