[tex]\boxed{AB = x}[/tex]
[tex]\boxed{BC = y}[/tex]
[tex]\boxed{AC = z}[/tex]
[tex]\boxed{AC = AB + BC}[/tex]
[tex]AC + AB = \frac{4}{3} (BC) \\ AB + BC + AB = \frac{4}{3} (BC) \\ 2AB + BC = \frac{4}{3} (BC) \\ 2AB = \frac{4}{3} (BC) - BC \\ 2AB = \frac{1}{3} (BC) \\ 2AB \times 3 = BC \\ 6AB = BC \\ \boxed{\frac{AB}{BC} = \frac{1}{6} }[/tex]
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Verified answer
☆ RESOLUCIÓN:
[tex]\boxed{AB = x}[/tex]
[tex]\boxed{BC = y}[/tex]
[tex]\boxed{AC = z}[/tex]
[tex]\boxed{AC = AB + BC}[/tex]
[tex]AC + AB = \frac{4}{3} (BC) \\ AB + BC + AB = \frac{4}{3} (BC) \\ 2AB + BC = \frac{4}{3} (BC) \\ 2AB = \frac{4}{3} (BC) - BC \\ 2AB = \frac{1}{3} (BC) \\ 2AB \times 3 = BC \\ 6AB = BC \\ \boxed{\frac{AB}{BC} = \frac{1}{6} }[/tex]
∴ RESPUESTA:
[tex]\boxed{ \frac{AB}{BC} = \frac{1}{6} }[/tex]
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