Question

Logaritmos // porfaaa ayuden

logx^3= log 6 + 2logx

Answer 1

log(x^3) = log(6)+2 log(x)

-log(6)-2 log(x)+log(x^3) = 0

-log(6)-2 log(x)+log(x^3) =
log(1/6)+log(1/x^2)+log(x^3) =
log(x^3/(6 x^2)) =
log(x/6)=
log(x/6) = 0
x/6=1
x = 6


saludos