Respuesta:
Explicación paso a paso:
1.
[tex]13^{2} =5^{2} +co^{2} \\169=25+co^{2} \\144=co^{2} \\12=co[/tex]
[tex]Tan\alpha = Co/Ca\\Tan\alpha =12/5\\Clave: c)[/tex]
2.
[tex]h^{2} =3^{2} +2^{2} \\h^{2} =9+4\\h=\sqrt{13}[/tex]
[tex]N=\sqrt{13} . Sen\alpha +3Cot\alpha \\N=\sqrt{13} . \frac{Co}{h} + 3.\frac{Ca}{Co} \\N=\sqrt{13} .\frac{3}{\sqrt{13} } +3. \frac{2}{3} \\N=3+2\\N=5\\Clave: c)[/tex]
3.
[tex]\sqrt{10} ^{2} =1+Co^{2} \\9=Co^{2} \\3=Co[/tex]
[tex]L=\frac{\sqrt{10} ^{2} }{1} +\frac{9}{1} \\L=10+9\\L=19\\Clave: e)[/tex]
4.
[tex]2x^{2} +4x+1=64+2x^{2} -4x+1\\8x=64\\x=8\\N=\frac{17}{8} +\frac{15}{8} \\N=\frac{32}{8}\\ N=4\\Clave: b)[/tex]
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Verified answer
Respuesta:
Explicación paso a paso:
1.
[tex]13^{2} =5^{2} +co^{2} \\169=25+co^{2} \\144=co^{2} \\12=co[/tex]
[tex]Tan\alpha = Co/Ca\\Tan\alpha =12/5\\Clave: c)[/tex]
2.
[tex]h^{2} =3^{2} +2^{2} \\h^{2} =9+4\\h=\sqrt{13}[/tex]
[tex]N=\sqrt{13} . Sen\alpha +3Cot\alpha \\N=\sqrt{13} . \frac{Co}{h} + 3.\frac{Ca}{Co} \\N=\sqrt{13} .\frac{3}{\sqrt{13} } +3. \frac{2}{3} \\N=3+2\\N=5\\Clave: c)[/tex]
3.
[tex]\sqrt{10} ^{2} =1+Co^{2} \\9=Co^{2} \\3=Co[/tex]
[tex]L=\frac{\sqrt{10} ^{2} }{1} +\frac{9}{1} \\L=10+9\\L=19\\Clave: e)[/tex]
4.
[tex]2x^{2} +4x+1=64+2x^{2} -4x+1\\8x=64\\x=8\\N=\frac{17}{8} +\frac{15}{8} \\N=\frac{32}{8}\\ N=4\\Clave: b)[/tex]