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Formula :
➡ A♦ =,D . d / 2
Donde:
D = Diagonal mayor = 22
d = diagonal menor = 15
Resolución
D . d / 2 =
⬆Reemplazamos
A♦ =22 . 15 / 2
A♦ =330 / 2
A♦ = 165
⬆El área del rombo es 165 .
El otro no estoy seguro por eso solo te aportare con la 1.
Un abrazo. ...C;