Question

por favor ayúdenme es para hoy

¹
10(−4x+3y)+(−6)(−x−y+2)


²
(−2)(4−2a+3x)−(−5)(9+5a−x)​

Answer 1

Respuesta:

¹

10(−4x+3y)+(−6)(−x−y+2)

[tex]=10\left(-4x+3y\right)-6\left(-x-y+2\right)\\=-40x+30y-6\left(-x-y+2\right)\\=-40x+30y+6x+6y-12\\=-34x+36y-12[/tex]

²

(−2)(4−2a+3x)−(−5)(9+5a−x)​

[tex]=-2\left(4-2a+3x\right)+5\left(9+5a-x\right)\\=-8+4a-6x+5\left(9+5a-x\right)\\=-8+4a-6x+45+25a-5x\\=-11x+29a+37[/tex]