Respuesta:
Explicación paso a paso:
a)[tex]\sqrt[3]{((-125)(343)} =\sqrt[3]{(-42875)}=-35[/tex]
b)[tex]\sqrt[3]{((-8^{12})/(-8^{6} )} =\sqrt[3]{((68719476.74E3})/(262144 )} =\sqrt[3]{((68719476.74E3})/(262144 )}=\sqrt[3]{262144} =64[/tex]
c)[tex]\sqrt[12]{(6^{4} )^{2} } =\sqrt[12]{(1296 )^{2} } =\sqrt[12]{(1679616 ) } =3.3019[/tex]
d)[tex]\sqrt[4]{((2^{8})*(3^{12})*(4^{4} )) } =\sqrt[4]{((256)*(531441)*(256 )) } =\sqrt[4](3.482851738E10) =432[/tex]
e) [tex]\sqrt{64*121} =\sqrt{7744} =88[/tex]
f) [tex]\sqrt[6]{((7^{6})*(2^{12} ) )} =\sqrt[6]{((117649)*(4096) )}=\sqrt[6]{(481890304)}=28[/tex]
g)[tex]\sqrt{\frac{729}{81} } =\sqrt{9} =3[/tex]
h) [tex]\sqrt[5]{((-32)*(-243))} =\sqrt[5]{(7776)}=6[/tex]
i) [tex]\sqrt[5]{((-3^{19})*(-5^{5} ))} =\sqrt[5]{(-1162261467)*(-3125)}=\sqrt[5]{3.632067084E12}=325.110[/tex]
j)[tex]\sqrt[16]{(-1)^{16} }= \sqrt[16]{1}= 1[/tex]
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Respuesta:
Explicación paso a paso:
a)[tex]\sqrt[3]{((-125)(343)} =\sqrt[3]{(-42875)}=-35[/tex]
b)[tex]\sqrt[3]{((-8^{12})/(-8^{6} )} =\sqrt[3]{((68719476.74E3})/(262144 )} =\sqrt[3]{((68719476.74E3})/(262144 )}=\sqrt[3]{262144} =64[/tex]
c)[tex]\sqrt[12]{(6^{4} )^{2} } =\sqrt[12]{(1296 )^{2} } =\sqrt[12]{(1679616 ) } =3.3019[/tex]
d)[tex]\sqrt[4]{((2^{8})*(3^{12})*(4^{4} )) } =\sqrt[4]{((256)*(531441)*(256 )) } =\sqrt[4](3.482851738E10) =432[/tex]
e) [tex]\sqrt{64*121} =\sqrt{7744} =88[/tex]
f) [tex]\sqrt[6]{((7^{6})*(2^{12} ) )} =\sqrt[6]{((117649)*(4096) )}=\sqrt[6]{(481890304)}=28[/tex]
g)[tex]\sqrt{\frac{729}{81} } =\sqrt{9} =3[/tex]
h) [tex]\sqrt[5]{((-32)*(-243))} =\sqrt[5]{(7776)}=6[/tex]
i) [tex]\sqrt[5]{((-3^{19})*(-5^{5} ))} =\sqrt[5]{(-1162261467)*(-3125)}=\sqrt[5]{3.632067084E12}=325.110[/tex]
j)[tex]\sqrt[16]{(-1)^{16} }= \sqrt[16]{1}= 1[/tex]