Question

Por favor alguien que me ayude con este taller de Química xf se los agradezco desde ya

Answer 1

17.  87.5 % N, 12.5 % H

Mm N = 14 g/mol

          H = 1 g/mol

N: 87.5 g / 14 g/mol = 6.25 mol

H: 12.5 g/ 1 g/mol = 12.5 mol

Dividir cada elemento entre el menor de los resultados

N: 6.26 mol / 6.25 mol = 1

H: 12.5 mol / 6.25 mol = 2

FE = N1H2

Mm de la FE

N: 1 x 14 = 14 /mol

H: 2 x 1 = 2 g/mol

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            Mm = 16 g/mol

n (moles) = 32 g/mol / 16 g/mol = 2

FM: (N1H2)2 = N2H4

16. Mm C: 12 x 1 = 12 g/mol

              H: 2 x 1 = 2 g/mol

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                    Mm = 14 g/mol

 n  (Moles) = 84 / 14 = 6

FM = (CH2)6 = C6H6