POMOŻECIE Z MATMĄ ? BARDZO MI ZALEŻY!
134.
a)
b)
c)
d)
135.
zad134
a)√(25-16)=√9=3
√(25:16)=√25/√16=5/4=1¼
√(25·16)=√400=20
b)√(1+9/16)=√(25/16)=5/4
√(25/4 -4 )=√(6¼-4)=√2¼=√9/4=3/2 =1½
√(6²+8²)=√(36+64)=√100=10
c)√√81=√(√9·√9)=√(3·3)=√9=3
√√0,0001=√(√0,01·√0,01)=√(0,1·0,1)=√0,01=0,1
√√2√64=√√(2·8)=√√16=√4=2
d)√∛(1/64)=√(1/4)=1/2
∛10⁶ =∛(1000 ·∛10000=10·10 =100
∛3√81=∛(3·9)=∛27=3
zad135
a)√2·√8=√16=4
b)∛16· ∛62,5=∛1000 =10
c)⁴√768 :₄√3= ⁴√256=4
d)(3∛2)³=9·2=18
e)(∛17²·∛17)²=(∛289 ·∛17)²=(∛4913)² =17²=289
f)(2√2)³ =8√8=8√4·√2=8·2·√2=16√2
g)√3⁶=√3³·√3³ =√27·√27=√729=27
h)⁴√5¹² =⁴√5⁴ ·⁴√5⁴ ·⁴√5⁴ =5·5·5=125
i)⁵√10¹⁰ =⁵√10⁵ ·⁵√10⁵ =10·10=100
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134.
a)
b)
c)
d)
135.
a)
b)![\sqrt[3]{16}\cdot\sqrt[3]{62,5}=\sqrt[3]{16\cdot62,5}}=\sqrt[3]{1000}=10 \sqrt[3]{16}\cdot\sqrt[3]{62,5}=\sqrt[3]{16\cdot62,5}}=\sqrt[3]{1000}=10](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16%7D%5Ccdot%5Csqrt%5B3%5D%7B62%2C5%7D%3D%5Csqrt%5B3%5D%7B16%5Ccdot62%2C5%7D%7D%3D%5Csqrt%5B3%5D%7B1000%7D%3D10)
c)![\sqrt[4]{768}:\sqrt[4]{3}=\sqrt[4]{768:3}=\sqrt[4]{256}=4 \sqrt[4]{768}:\sqrt[4]{3}=\sqrt[4]{768:3}=\sqrt[4]{256}=4](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B768%7D%3A%5Csqrt%5B4%5D%7B3%7D%3D%5Csqrt%5B4%5D%7B768%3A3%7D%3D%5Csqrt%5B4%5D%7B256%7D%3D4)
zad134
a)√(25-16)=√9=3
√(25:16)=√25/√16=5/4=1¼
√(25·16)=√400=20
b)√(1+9/16)=√(25/16)=5/4
√(25/4 -4 )=√(6¼-4)=√2¼=√9/4=3/2 =1½
√(6²+8²)=√(36+64)=√100=10
c)√√81=√(√9·√9)=√(3·3)=√9=3
√√0,0001=√(√0,01·√0,01)=√(0,1·0,1)=√0,01=0,1
√√2√64=√√(2·8)=√√16=√4=2
d)√∛(1/64)=√(1/4)=1/2
∛10⁶ =∛(1000 ·∛10000=10·10 =100
∛3√81=∛(3·9)=∛27=3
zad135
a)√2·√8=√16=4
b)∛16· ∛62,5=∛1000 =10
c)⁴√768 :₄√3= ⁴√256=4
d)(3∛2)³=9·2=18
e)(∛17²·∛17)²=(∛289 ·∛17)²=(∛4913)² =17²=289
f)(2√2)³ =8√8=8√4·√2=8·2·√2=16√2
g)√3⁶=√3³·√3³ =√27·√27=√729=27
h)⁴√5¹² =⁴√5⁴ ·⁴√5⁴ ·⁴√5⁴ =5·5·5=125
i)⁵√10¹⁰ =⁵√10⁵ ·⁵√10⁵ =10·10=100