Question

pomocy z tymi 3 zadaniami XD daje naj!!


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Answer 1

Verified answer

Odpowiedź:

zad.31.

a) [tex]3-\frac{4}{3} =\frac{9}{3} -\frac{4}{3} =\frac{5}{3} =1\frac{2}{3}[/tex]

b) [tex]-\frac{23}{4} +\frac{8}{3} =-\frac{69}{12}+\frac{32}{12} =-\frac{37}{12}=-3\frac{1}{12}[/tex]

c) [tex]\frac{9}{2} :(0,5-0,125)=\frac{9}{2} :(0,375)=\frac{9}{2} :\frac{3}{8} =\frac{9}{2} *\frac{8}{3} =\frac{36}{3} =12[/tex]

d) [tex]\frac{0,0625+0,25}{-3} =\frac{0,3125}{-3} =-0,1[/tex]

zad.32.

a) [tex]-4,56*(-5)=22,8[/tex]

b) [tex](-2,1)^3=-9,3[/tex]

c) [tex]-0,3*(-0,25)^2=-0,3*0,0625=-0,019[/tex]

d) [tex]-4,2:(-0,6)=7[/tex]

zad.33.

a) [tex]4,35-(-\frac{5}{3} )=4,35+1,67=6,02[/tex]

b) [tex]-\frac{18}{5} -5,2=-3,6-5,2=-8,8[/tex]

c) [tex]-\frac{68}{9} +3,4=-7,56+3,4=-4,16[/tex]

d) [tex]-8,4-(-\frac{17}{8} )=-8,4+2,125=-6,275[/tex]

Szczegółowe wyjaśnienie: