Pomocy!!!!!!!!!!! Rozwiąż układ równań: (y-2x)2+8x(y+1)=(2x+y)(y+2x)+y+1 (1-3x)(1+3x)+y=3-(1-3x)2 W odpowiedziach x to 1 ,a y to 7
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(y-2x)2+8x(y+1)=(2x+y)(y+2x)+y+1
(1-3x)(1+3x)+y=3-(1-3x)2
y² - 4xy + 4x² + 8xy + 8x = 2xy + 4x² + y² + 2xy + y + 1
1 - 9x² + y = 3 - 1 + 6x - 9x²
y² - y² - 4xy + 8xy - 2xy - 2xy + 4x² - 4x² + 8x - y = 1
-9x² + 9x² + y - 6x = 1
8x - y = 1
-6x + y = 1
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8x - 6x - y + y = 1 + 1
2x = 2 /: 2
x = 1
8 * 1 - y = 1
-y = 1 - 8
-y = -7
y = 7