Odpowiedź:
a)
[tex]ab=cd |:c\\d = \frac{ab}{c}[/tex]
b)
[tex]\frac{a^2b}{c} = cd | * c\\ a^2b=c^2d |:b\\a^2 = \frac{c^2d}{b} | * \sqrt{} \\a = \sqrt{ \frac{c^2d}{b} }[/tex]
c)
[tex]\frac{al}{c} = \frac{ml}{k} \\alk = mlc | : ml\\c = \frac{alk}{ml} = \frac{ak}{m}[/tex]
Wyjaśnienie:
W razie pytań pisz kom :D
A) ab=cd / :c
d=(ab)/c
b)(a²b)/c=cd / *c
a²b=c²d / :b
a²=(c²d)/b
a= pierwiastek z [(c²d)/b]
c) (dl)/c=(ml)/k /*c
dl=(mlc)/k /*k
dlk=mlc / :ml
c=(dlk/ml
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Verified answer
Odpowiedź:
a)
[tex]ab=cd |:c\\d = \frac{ab}{c}[/tex]
b)
[tex]\frac{a^2b}{c} = cd | * c\\ a^2b=c^2d |:b\\a^2 = \frac{c^2d}{b} | * \sqrt{} \\a = \sqrt{ \frac{c^2d}{b} }[/tex]
c)
[tex]\frac{al}{c} = \frac{ml}{k} \\alk = mlc | : ml\\c = \frac{alk}{ml} = \frac{ak}{m}[/tex]
Wyjaśnienie:
W razie pytań pisz kom :D
A) ab=cd / :c
d=(ab)/c
b)(a²b)/c=cd / *c
a²b=c²d / :b
a²=(c²d)/b
a= pierwiastek z [(c²d)/b]
c) (dl)/c=(ml)/k /*c
dl=(mlc)/k /*k
dlk=mlc / :ml
c=(dlk/ml