POMOCY!!!!!
Potrzebuje na dzisiaj 3 zadań z fizyki (termodynamika) to PILNE!!!
1. Jaka ilość ciepła jest potrzebna ,aby doprowadzić do wrzenia 1kg wody o temperaturze 10°C? Ciepło właściwe
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1.
m = 1kg
T = 10⁰C
Cw = 4200J/kg*⁰C
Q = m*ΔT*Cw
Q = 1kg*90⁰C*4200J/kg*⁰C
Q = 378000 J = 378kJ
2.
m = 2kg
Q = 84kJ
Cw = 4200J/kg*⁰C
Q = m*ΔT*Cw
ΔT = Q/m*Cw
ΔT = 84000J:4200J/kg*⁰C*2kg
ΔT = 10⁰C
3.
v₁ = 500m/s
v₂ = 300m/s
m = 20g = 0,02kg
mv₁²/2 = mv₂²/2 + Q
Q = mv₁²/2-mv₂²/2
Q = ½*m(v₁²-v₂²)
Q = ½*0.02kg*[(500m/s)²-(300m/s)²]
Q = 0,01kg(250000m²/s²-90000m²/s²)
Q = 1600J = 1,6kJ