POMOCY!!!! kto pomoze rozwiazac?
(x-1)(x+2)(x-5)/ (x^2-10x+25) = 0
zal. x^2-10x+25≠0
(x-5)^2≠0
x≠5
(x-1)(x+2)(x-5)(x-5)^2=0
(x-1)(x+2)(x-5)^3=0
x=1 v x= -2 v x= 5 <-- spr. z zalozeniem
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(x-1)(x+2)(x-5)/ (x^2-10x+25) = 0
zal. x^2-10x+25≠0
(x-5)^2≠0
x≠5
(x-1)(x+2)(x-5)(x-5)^2=0
(x-1)(x+2)(x-5)^3=0
x=1 v x= -2 v x= 5 <-- spr. z zalozeniem