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[(x²-2)²-2x²]·[(x²-2)²+2x²]=
(x⁴-4x²+4-2x²)((x⁴-4x²+4+2x²)=
(x⁴-6x²+4)(x⁴-2x²+4)=
Δ1=36-16=20⇒√Δ=2√5
(x⁴-6x²+4)=[x²-(3-√5)][x²-(3+√5)]
Δ2=4-16=-12
ODP
[x²-(3-√5)][x²-(3+√5)]·(x⁴-2x²+4)
x²-(3-√5)=[x-√(3-√5)][x+√(3-√5)]
x²-(3+√5)=[x-√(3+√5)][x+√(3+√5)]
Pozdr
J