pomóżcie obliczyć: (2⁻¹+1)⁻¹+(-4)²×(-⅙)²-(⅓)⁻²=
(2⁻¹+1)⁻¹+(-4)²×(-⅙)²-(⅓)⁻²=
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(2⁻¹+1)⁻¹+(-4)²×(-⅙)²-(⅓)⁻²=