pomóżcie na teraz potrzebuje
a do 3=512
a=8
pole powierzchni
8*8*6=384
1 c
2 d
3
3- √48 = √9 - 4√3 = √3 · ( √3 - 4 )
4
3√2 + 5 = 3√2 + 5√2 = 42√2 + 5√2 = 47√2
7√2 14 14 14
5
512= a³
a= 8
P = 6a²
P= 6 ·64
P= 384
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a do 3=512
a=8
pole powierzchni
8*8*6=384
1 c
2 d
3
3- √48 = √9 - 4√3 = √3 · ( √3 - 4 )
4
3√2 + 5 = 3√2 + 5√2 = 42√2 + 5√2 = 47√2
7√2 14 14 14
5
512= a³
a= 8
P = 6a²
P= 6 ·64
P= 384