Pomóżcie. : <
4(x2-3x+2)+5x2+12x-1=
-2(a+4)+3(2a-6)=
3x(x-1)-4x(2x+3)=
ta dwójka np po "x" to chodzi że do kwadratu.
4(x²-3x+2)+5x²+12x-1=4x²-12x+8+5x²+12x-1= 9x²+7
-2(a+4)+3(2a-6)=-2a-8+6a-12=4a-20
3x(x-1)-4x(2x+3)=3x²-3x-8x²-12x=-5x²-15x
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4(x²-3x+2)+5x²+12x-1=4x²-12x+8+5x²+12x-1= 9x²+7
-2(a+4)+3(2a-6)=-2a-8+6a-12=4a-20
3x(x-1)-4x(2x+3)=3x²-3x-8x²-12x=-5x²-15x