pole trojkata o bokach 2 i 4 oraz kacie zawartym miedzy tymi bokami 30 stopni wynosi. prosze o rozwiazanie
P=1/2*2*4*sin30
P=4*1/2
P=2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
P=1/2*2*4*sin30
P=4*1/2
P=2