Question

pole rownolegloboku wynosi 120cm2. jeden z bokow ma dlugosc 5cm, a jedna z wysokosci 4cm. oblicz drugi bok i druga wysokość.

prosze o dane rozwiazaanie i odpowiedz dam naj

Answer 1

z.1

P = 120 cm^2

b = 5 cm

h1 = 4 cm

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a = ?

h2 = ?

Mamy

P = a *h1

a = P : h1 = 120 cm^2 : 4 cm = 30 cm

P = b*h2

h2 = P : b = 120 cm^2 : 5 cm = 24 cm

Odp. a = 30 cm, h2 = 24 cm.

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spr. a*h1 = b*h2

30 cm * 4 cm = 5 cm * 24 cm

120 cm^2 = 120 cm^2

Answer 2

wzor na pole rownolegloboku

 

P=a*h a

lub            P=b*h b

 

h a-wysokosc opuszczona na bok a

 

h b- wysokosc opuszczona na bok b

 

P=120 cm²

h a=4cm

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a=?

 

                             P=a*h a

                            

                            120=a*4

 

                           a=30 cm

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P=120 cm²

b=5 cm

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h b=?

 

                                   P=b*h b

                                 120=5*h b

                                    h b=120/5

                                 h b=24 cm

 

Dluzszy bok ma 30 cm, a druga wysokosc 24 cm

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