pole rombu o boku 5cmi jednej z przyprostokątnych wynosi 6cm
5²=3²+x²
25=9+x²
x²=25-9
x²=16
x=4
e=6cm
f=2*4cm=8cm
P=½*6*8=24 cm²
5*5 = 3 * 3 + x * x
25 = 9 + x * x
x * x = 25 - 9
x * x = 16
x = 4
e = 6 cm
f = 2 * 4 cm = 8 cm, czyli
P= 0,5 * 6 * 8 = 24 cm kwadratowe
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5²=3²+x²
25=9+x²
x²=25-9
x²=16
x=4
e=6cm
f=2*4cm=8cm
P=½*6*8=24 cm²
5*5 = 3 * 3 + x * x
25 = 9 + x * x
x * x = 25 - 9
x * x = 16
x = 4
e = 6 cm
f = 2 * 4 cm = 8 cm, czyli
P= 0,5 * 6 * 8 = 24 cm kwadratowe