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(a-3) *(b+3) =256
wiedząc że 256 to pole kwadratu to:
(a-3)=(b+3)
√256=16
a-3 = 16
a=19
b+3=16
b=13
z pitagorasa
d²=a² +b²
d²= 19² +13²
d²=361 + 169
d²=530
d=√530
Odp: √530