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Odp. Powinien to być sześcian o krawędzi 2cm
a*h=24-2*a² /:a
h=(24-2*a²)/a
v=a²*h=a²*(24-2*a²)/a
v=a*(24-2*a²)=24*a-2*a³
f(x)=-2*a³+24*a
f'(x)=-6a²+24
f'(x)=0
-6*a²+24=0
6(4-a²)=0
6(2-a)(2+a)=0
a=2 lub a=-2⇒∈Ф