Pole okregu opisanego na trójkącie równobocznym jest równe 16 cm. Oblicz pole i obwód trojkata
P = πr²
16π = πr²
r² = 16
r = √16
r = 4
r = 2/3h
h = 6
h = a√3/2
6 = a√3/2 /*2
12 = a√3 //:√3
12/√3 = a
12√3/3 = a
a = 4√3
P = a²√3/4
P = (4√3)²√3/4
p = 48√3/4
p = 12√3
Ob= 4√3*3
Ob= 12√3
Liczę na naj :)
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P = πr²
16π = πr²
r² = 16
r = √16
r = 4
r = 2/3h
h = 6
h = a√3/2
6 = a√3/2 /*2
12 = a√3 //:√3
12/√3 = a
12√3/3 = a
a = 4√3
P = a²√3/4
P = (4√3)²√3/4
p = 48√3/4
p = 12√3
Ob= 4√3*3
Ob= 12√3
Liczę na naj :)