Pole kwadratu opisanego na kole o obwodzie 8 pi cm równe jest?
l=2πr l=8πcm
8π=2πr
r=8π:2π=4
r=4cm
r=a/2 4=a/2 a=4·2=8cm---bok kwadratu
P=8²=64cm²
odp:pole tego kwadratu wynosi 64cm²
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l=2πr l=8πcm
8π=2πr
r=8π:2π=4
r=4cm
r=a/2 4=a/2 a=4·2=8cm---bok kwadratu
P=8²=64cm²
odp:pole tego kwadratu wynosi 64cm²